Σᵢ₌₁ⁿ i³ = [n(n + 1) / 2]²Variables
- n
- positive integer
Reference details
- Subject
- Number Theory
- Topic
- sums
- Plain text
sum i=1 to n i^3=[n(n+1)/2]^2
Number Theory · sums
Sum of First n Cubes Formula
Finds the sum of cubes from 1³ through n³.
Number Theory · sums
Finds the sum of cubes from 1³ through n³.
Σᵢ₌₁ⁿ i³ = [n(n + 1) / 2]²sum i=1 to n i^3=[n(n+1)/2]^2